![]() The edges of a triangular board are 6 cm, 8 cm and 10 cm. The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is (iii) Equate the area obtained using the two formula’s and obtain the required height. (ii) For the longest altitude, take base as the smallest side. (i) First, determine the semi-perimeter, s and then determine the area of triangle by using Heron’s formula. The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. Hence, the perimeter of an equilateral triangle is 24 cm. Perimeter of an equilateral triangle = 3 x Side= 3 x 8 = 24 cm (b) Given, area of an equilateral triangle = 16√3 cm 2Īrea of an equilateral triangle = √3/4 (side) 2 If the area of an equilateral triangle is 16√3 cm 2, then the perimeter of the triangle is Hence, the length of an equilateral triangle is 6 cm. ∴ Area of an equilateral triangle = √3/4(Side) 2 (d) Given, area of an equilateral triangle = 9√3 cm 2 The length of each side of an equilateral triangle having an area of 9√3 cm 2 is Hence, the area of an equilateral triangle is 5.196 cm 2. (a) Given, side of an equilateral triangle is 2√3 cm.Īrea of an equilateral triangle = √3/4 (Side) 2 The area of an equilateral triangle with side 2√3 cm is (ii) Further, determine the area of triangle by using the formula, area of triangle (Fieron’s formula) = (i) First, determine the semi-perimeter of a triangle by using the formula, s = (a + b + c)/2 The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, perimeter of an equilateral triangle = 60 m (d) Let each side of an equilateral be x. (ii) Further, substitute the value of x in the formula, area of an equilateral triangle = √3/4 (a) 2 and simplify it. (i) First, determine the side of an equilateral by usingformula, perimeter=3x. The perimeter of an equilateral triangle is 60 m. ![]() Hence, the length of its hypotenuse is √32 cm. (a) Given, area of an isosceles right triangle = 8 cm 2Īrea of an isosceles triangle = ½ (Base x Height) An isosceles right triangle has area 8 cm 2.
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